15 posts
can any1 help with this qn?
zero.
not 0 meh?
Originally posted by jay_rocks: not 0 meh?
hmm but hor i sub 0 into x den 0^1/pi = math error on the calcualtor
Originally posted by gobez14: hmm but hor i sub 0 into x den 0^1/pi = math error on the calcualtor
PAiseh paiseh the question supposed to be x^-1/pi = 0
Originally posted by gobez14: PAiseh paiseh the question supposed to be x^-1/pi = 0
not possible as x^(-1/pi) is always positive for all real values of x.
x is infinity
TS means x^(-1/pi)=0 answer, (1/x)^(1/pi) = 0 1/( pi root(x) ) = 0 x = 0 which means x must be zero...
Originally posted by popikachu: x^-1/pi = 0 x^-1 = 0 1/x= 0 1 = 0
i tink TS meant x^-(1/pi) = 0 dam...i totally forgotten wat to do...NS has made me stupid
x is undefined. x is infinity only when 1/x approaches zero but not zero itself.
Originally posted by popikachu: TS means x^(-1/pi)=0 answer, (1/x)^(1/pi) = 0 1/( pi root(x) ) = 0 x = 0 which means x must be zero...
1/( pi root(x) ) = 0 1/0=pi root(x) use your calculator and punch in 1 divided by 0.
(x^-1)/pi=0 therefore, we can say that x^-1=0 which means 1/x=0 there for, x= infniti when x approaches to 0 scenario 2 x^(-1/pi)=0 root (-1/pi) both sides. therefore x=0.
x^-(1/pi) = 0 ln (x^-(1/pi)) = ln 0 (-1/pi)ln(x)=1 ln x = -pi x = exp^-pi) forget some of the natural log rules, hopefully i'm correct.
Originally posted by 798: x^-(1/pi) = 0 ln (x^-(1/pi)) = ln 0 (-1/pi)ln(x)=1 ln x = -pi x = exp^-pi) forget some of the natural log rules, hopefully i'm correct.
ln 0 is undefined
Originally posted by HyuugaNeji: ln 0 is undefined
tis part i quite confuse... cos i do not have matlab wif me.
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15 posts
15 posts
ln (x^-(1/pi)) = ln 0