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Physics - Kinematics

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  • bonkysleuth's Avatar
    314 posts since Mar '07
    • I've got some questions that require some assistance from you guys. Appreciate your help.

       

      1. You walk a distance of 2km at an average speed of 6km/h. You then run for a further 10 minutes with an average speed of 12km/h. What is your average velocity for the whole journey?

       

      My answer's 8ms-1. Please check to see if you end up with the same as mine. If not, please highlight my errors. Thanks.

       

      2. A Toyota Corolla starts from rest and accelerates at 1.5m/s2. After what time would its velocity be 20m/s?

       

      I'm not pretty sure about this. But it should be something like 13.3333 secs when you divide 20 by 1.5? Or is it not?

       

      3a. When a velocity is increasing, acceleration is _______

      I wrote increasing

       

      3b. When velocity is decreasing, acceleration is ____

      I wrote decreasing

       

      3c. When the velocity is constant, acceleration is ____

      I wrote zero.

       

      Thanks for your guidance.

       

       

  • HyuugaNeji's Avatar
    1,648 posts since Jun '05
    • Originally posted by bonkysleuth:

      I've got some questions that require some assistance from you guys. Appreciate your help.

       

      1. You walk a distance of 2km at an average speed of 6km/h. You then run for a further 10 minutes with an average speed of 12km/h. What is your average velocity for the whole journey?

       

      My answer's 8ms-1. Please check to see if you end up with the same as mine. If not, please highlight my errors. Thanks.8km-1

       

      2. A Toyota Corolla starts from rest and accelerates at 1.5m/s2. After what time would its velocity be 20m/s?

       

      I'm not pretty sure about this. But it should be something like 13.3333 secs when you divide 20 by 1.5? Or is it not?

       v=u + at

      20= 0+1.5t

      t=13.33

      3a. When a velocity is increasing, acceleration is _______

      I wrote increasing

      positive. It is not necessary increasing. Acceleration can be decreasing and yet, the velocity is still increasing.

       

      3b. When velocity is decreasing, acceleration is ____

      I wrote decreasing

       negative. similar case.

      3c. When the velocity is constant, acceleration is ____

      I wrote zero.

      zero

       

      Thanks for your guidance.

       

       

       

      answers in bold

      Edited by HyuugaNeji 09 Feb `08, 6:26PM
  • bonkysleuth's Avatar
    314 posts since Mar '07
    • I don't kind of get what you're trying to say. I heard of situations where acceleration decreases and yet velocity is increasing. But in what sort of circumstances does this happen?

  • LatecomerX's Avatar
    2,331 posts since May '07
    • Originally posted by bonkysleuth:

      I don't kind of get what you're trying to say. I heard of situations where acceleration decreases and yet velocity is increasing. But in what sort of circumstances does this happen?

      When the acceleration is still positive, even if it is decreasing, the velocity is still increasing, but at a rate that is lower over time. The velocity graph would be something like half a neh. Acceleration is zero at the nipple, before it gets negative. See the first graph I found through Google below.

       

       

      Edited by LatecomerX 09 Feb `08, 8:57PM
  • LatecomerX's Avatar
    2,331 posts since May '07
  • Moderator
    Darkness_hacker99's Avatar
    31,746 posts since Jun '05
    • Originally posted by bonkysleuth:

      I don't kind of get what you're trying to say. I heard of situations where acceleration decreases and yet velocity is increasing. But in what sort of circumstances does this happen?

      I am not sure if this example is the right one of not.

      Imagine a rocket in sky travelling downward towards an object straight down. With the rocket's booster working, the velocity of the rocket is increasing due to the accerleration cause by the booster. But when the booster is jettison, the acceleration decreases but velocity still keep on increase..

      Have to relate it back to gravity, mass,energy,weight, and accerlation due gravity.

  • Moderator
    Darkness_hacker99's Avatar
    31,746 posts since Jun '05
  • Maith's Avatar
    2,695 posts since Dec '07
  • nightzip's Avatar
    5,745 posts since Oct '04
    • Originally posted by bonkysleuth:

      I've got some questions that require some assistance from you guys. Appreciate your help.

       

      1. You walk a distance of 2km at an average speed of 6km/h. You then run for a further 10 minutes with an average speed of 12km/h. What is your average velocity for the whole journey?

       

      My answer's 8ms-1. Please check to see if you end up with the same as mine. If not, please highlight my errors. Thanks.

      Average vel = total dist/total time Total dist = 2000m + 2000m = 4km Total time = 2/6hr+ 1/6hr = 20min+10min = 30min Average vel = 4/(1/2)=8 km/hr

       

      2. A Toyota Corolla starts from rest and accelerates at 1.5m/s2. After what time would its velocity be 20m/s?

       

      I'm not pretty sure about this. But it should be something like 13.3333 secs when you divide 20 by 1.5? Or is it not?

       

      3a. When a velocity is increasing, acceleration is _______

      I wrote increasing

      Wrong! When a velocity is CHANGING, acceleration is NON-ZERO. Thus, when a velocity is increasing, acceleration can also be a positive CONSTANT or an increasing value.

       

      3b. When velocity is decreasing, acceleration is ____

      I wrote decreasing

       

      3c. When the velocity is constant, acceleration is ____

      I wrote zero.

       

      Thanks for your guidance.

       

       

       

      Edited by nightzip 24 Feb `08, 10:49PM
  • Choya's Avatar
    6 posts since Feb '08
    • 3a. When a velocity is increasing, acceleration is positive

      3b. When velocity is decreasing, acceleration is negative

       

  • deathvale's Avatar
    19 posts since Feb '08
    • 1. the answer is 8 km/h not 8 m/s

      2. i'm assuming acceleration is constant. so i use v=u+at

      20=0+1.5t

      t=13.3s (same answer as yours)

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