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help solve this qn thankew

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  • gobez14's Avatar
    1,364 posts since Apr '07
    • given that y=2x^2 + px +16 and that y < 0 only when 2 < x < k, find the value of p and of k

       

  • tanjun's Avatar
    1,057 posts since Jan '05
    • y = 2x^2 + px + 16

      This curve is a U shaped curve with its roots at 2 and k respectively.

      Using Remainder and Factor Theorem

       

      let f(x) = 2x^2 + px + 16

      f(2) = 0, f(k) = 0

      8 + 2p + 16 = 0

      24 + 2p = 0

      p = -12

       

      2k^2 - 12k + 16 = 0

      k^2 - 6k + 8 = 0

      (k - 2)(k - 4) = 0

      k = 2 or k = 4

       

      k = 2 is rejected since k must be bigger than 2.

       

      Therefore, k = 4, p = -12

       

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