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    <title>Recent Posts in 'Physics help required' | sgForums.com</title>
    <link>http://politics.sgforums.com/forums/2297/topics/309959</link>
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      <title>Physics help required replied by WoAiMeiMei @ Sat, 08 Mar 2008 19:47:51 +0800</title>
      <description>&lt;p&gt;if the answer for the last question is dimensionally correct,
apparently it will produce these 2 answers:&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;L=0.64 m and Kmax=0.031 J&lt;/p&gt;</description>
      <pubDate>Sat, 08 Mar 2008 19:47:51 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:309959:7915456</guid>
      <author>WoAiMeiMei</author>
      <link>http://politics.sgforums.com/forums/2297/topics/309959</link>
    </item>
    <item>
      <title>Physics help required replied by eagle @ Fri, 07 Mar 2008 21:03:06 +0800</title>
      <description>&lt;blockquote&gt;
&lt;p&gt;3) A thin uniform rod with mass m swings about an axis that
passes through one end of the rod and is perpendicular to the plane
of the swing. The rod swings with a period T and an angular
amplitude of &#966;m (assume this angle is sufficiently small to allow
for the use of the equations in this chapter). (a) What is the
length of the rod? (b) What is the maximum kinetic energy of the
rod as it swings? State your answers in terms of the given
variables, using g and &#960; when applicable.&lt;/p&gt;
&lt;/blockquote&gt;
&lt;p&gt;a) cannot remember if it is done like that...&lt;/p&gt;
&lt;p&gt;let length be 2L, so CG of rod is at length L from the pivot&lt;/p&gt;
&lt;p&gt;T = 2&#960; sqrt (L/g)&lt;br /&gt;
Hence, L = (T/2&#960;)^2 * g&lt;/p&gt;
&lt;p&gt;Length of rod = 2L = 2 * (T/2&#960;)^2 * g&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;b) At amplitude, vertical distance of CG from pivot = L cos
&#966;m&lt;br /&gt;
Hence, PE gained from rest point = mgL (1 - cos &#966;m)&lt;br /&gt;
KE = 0 at this point&lt;/p&gt;
&lt;p&gt;At max KE, PE = 0&lt;br /&gt;
By conservation of energy, max KE = mgL (1 - cos &#966;m)&lt;/p&gt;</description>
      <pubDate>Fri, 07 Mar 2008 21:03:06 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:309959:7913559</guid>
      <author>eagle</author>
      <link>http://politics.sgforums.com/forums/2297/topics/309959</link>
    </item>
    <item>
      <title>Physics help required replied by eagle @ Fri, 07 Mar 2008 20:56:03 +0800</title>
      <description>&lt;p&gt;2) At t=0&lt;/p&gt;
&lt;p&gt;x = x&lt;em&gt;&lt;sub&gt;m&lt;/sub&gt;&lt;/em&gt;cos(&#960;/9)&lt;br /&gt;
PE = 1/2 k x^2 = 1/2 k [ &lt;em&gt;x&lt;sub&gt;m&lt;/sub&gt;&lt;/em&gt;cos(&#960;/9) ]^2&lt;/p&gt;
&lt;p&gt;v = dx/dt = -&#969;&lt;em&gt;x&lt;sub&gt;m&lt;/sub&gt;&lt;/em&gt;sin(&#969;t + &#966;) =
-&#969;&lt;em&gt;x&lt;sub&gt;m&lt;/sub&gt;&lt;/em&gt;sin(&#960;/9)&lt;br /&gt;
KE = 1/2 m v^2 = 1/2 m [&#969;&lt;em&gt;x&lt;sub&gt;m&lt;/sub&gt;&lt;/em&gt;sin(&#960;/9)] ^2&lt;br /&gt;
But &#969; = 2&#960; / T and T = 2&lt;span&gt;&#960; sqrt (m/k)&lt;br /&gt;
hence,&lt;/span&gt; &#969;^2 = k/m&lt;/p&gt;
&lt;p&gt;Thus, KE =1/2 k [ &lt;em&gt;x&lt;sub&gt;m&lt;/sub&gt;&lt;/em&gt;sin(&#960;/9)] ^2&lt;/p&gt;
&lt;p&gt;So, KE/PE = cos(&#960;/9)^2 / sin(&#960;/9)^2 = [ tan(&#960;/9) ]^2&lt;/p&gt;
&lt;p&gt;Ans: 0.132&lt;/p&gt;</description>
      <pubDate>Fri, 07 Mar 2008 20:56:03 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:309959:7913543</guid>
      <author>eagle</author>
      <link>http://politics.sgforums.com/forums/2297/topics/309959</link>
    </item>
    <item>
      <title>Physics help required replied by WoAiMeiMei @ Fri, 07 Mar 2008 13:50:27 +0800</title>
      <description>&lt;p&gt;hmm correction for q2 is:&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;If the phase angle for a block-spring system in SHM is &#960;/9 rad
and the block's position is given by &lt;em&gt;x&lt;/em&gt; =
&lt;em&gt;x&lt;sub&gt;m&lt;/sub&gt;&lt;/em&gt;cos(&#969;t + &#966;), what is the ratio of the kinetic
energy to the potential energy at time &lt;em&gt;t&lt;/em&gt; = 0?&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;change: &#960;/9 rad&lt;/p&gt;</description>
      <pubDate>Fri, 07 Mar 2008 13:50:27 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:309959:7912881</guid>
      <author>WoAiMeiMei</author>
      <link>http://politics.sgforums.com/forums/2297/topics/309959</link>
    </item>
    <item>
      <title>Physics help required replied by WoAiMeiMei @ Fri, 07 Mar 2008 13:19:56 +0800</title>
      <description>&lt;p&gt;yeah sorry i dont have answers ey...&lt;/p&gt;</description>
      <pubDate>Fri, 07 Mar 2008 13:19:56 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:309959:7912806</guid>
      <author>WoAiMeiMei</author>
      <link>http://politics.sgforums.com/forums/2297/topics/309959</link>
    </item>
    <item>
      <title>Physics help required replied by eagle @ Fri, 07 Mar 2008 13:16:26 +0800</title>
      <description>&lt;p&gt;Please post the answers if you have them (Homework Forum
guidelines)&lt;/p&gt;
&lt;p&gt;Either someone will help you, or I find some time tonight to do
the rest... The first question is to help you get started....&lt;/p&gt;</description>
      <pubDate>Fri, 07 Mar 2008 13:16:26 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:309959:7912800</guid>
      <author>eagle</author>
      <link>http://politics.sgforums.com/forums/2297/topics/309959</link>
    </item>
    <item>
      <title>Physics help required replied by WoAiMeiMei @ Fri, 07 Mar 2008 13:14:21 +0800</title>
      <description>&lt;p&gt;yay thanks eagle.. the first one is correct.&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;the last one is the hardest apparently &amp;gt;.&amp;lt;&lt;/p&gt;</description>
      <pubDate>Fri, 07 Mar 2008 13:14:21 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:309959:7912796</guid>
      <author>WoAiMeiMei</author>
      <link>http://politics.sgforums.com/forums/2297/topics/309959</link>
    </item>
    <item>
      <title>Physics help required replied by eagle @ Fri, 07 Mar 2008 12:58:31 +0800</title>
      <description>&lt;p&gt;I think:&lt;/p&gt;
&lt;p&gt;1) a)&lt;/p&gt;
&lt;p&gt;Equation: a = -&lt;span style=""&gt;&#969;2x&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;So &lt;span style=""&gt;&#969;2 = -a / x = 1382.857&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;span style=""&gt;Thus &#969; = 2&lt;/span&gt;&lt;span style=""&gt;&#960;f =
37.186787&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;f = 5.92 Hz&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;b) T = 2&lt;span style=""&gt;&#960; sqrt (m/k)&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;But T (period) = 1/f&lt;/p&gt;
&lt;p&gt;m = 0.332 kg (3 sf)&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;c) &lt;span style="font-family: arial,helvetica;"&gt;x = Acos(wt+f) --
(1)&lt;br /&gt;
v = dx/dt = -wAsin(wt+f) =&amp;gt;&lt;/span&gt; &lt;span style=
"font-family: arial,helvetica;"&gt;Asin(wt+f) = -V /&lt;/span&gt;
&lt;span style="font-family: arial,helvetica;"&gt;w --
(2)&lt;br /&gt;&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;(1) ^2 + (2) ^2 = A^2&amp;nbsp; = x^2 + (-V/&lt;span style=
"font-family: arial,helvetica;"&gt;w )&lt;/span&gt;^&lt;span style=
"font-family: arial,helvetica;"&gt;2&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;So using the instant where x = 0.0875 and V = -17.5&lt;/p&gt;
&lt;p&gt;A = 0.479 m&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;Someone confirm for me because no answer was posted...&lt;br /&gt;
And lazy to do Q2 and Q3 right now.&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;</description>
      <pubDate>Fri, 07 Mar 2008 12:58:31 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:309959:7912749</guid>
      <author>eagle</author>
      <link>http://politics.sgforums.com/forums/2297/topics/309959</link>
    </item>
    <item>
      <title>Physics help required replied by WoAiMeiMei @ Thu, 06 Mar 2008 18:16:54 +0800</title>
      <description>&lt;p&gt;actually i need help &amp;gt;.&amp;lt;&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&lt;br /&gt;
1) An oscillator consists of a block attached to a spring (k = 460
N/m). At some time t, the position (measured from the system's
equilibrium location), velocity, and acceleration of the block are
x = 0.0875 m, v = -17.5 m/s, and a = -121 m/s2. Calculate (a) the
frequency (in Hz) of oscillation, (b) the mass of the block, and
(c) the amplitude of the motion.&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
2) If the phase angle for a block-spring system in SHM is &#960;/9 rad
and the block's position is given by x = xmcos(&#969;t + &#966;), what is the
ratio of the kinetic energy to the potential energy at time t =
0?&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
3) A thin uniform rod with mass m swings about an axis that passes
through one end of the rod and is perpendicular to the plane of the
swing. The rod swings with a period T and an angular amplitude of
&#966;m (assume this angle is sufficiently small to allow for the use of
the equations in this chapter). (a) What is the length of the rod?
(b) What is the maximum kinetic energy of the rod as it swings?
State your answers in terms of the given variables, using g and &#960;
when applicable.&lt;/p&gt;</description>
      <pubDate>Thu, 06 Mar 2008 18:16:54 +0800</pubDate>
      <guid isPermaLink="false">politics.sgforums.com:2297:309959:7910418</guid>
      <author>WoAiMeiMei</author>
      <link>http://politics.sgforums.com/forums/2297/topics/309959</link>
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