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Loginemergency electrical help needed >_<
15 posts
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Q3
For V1 to be 0, the potential in between R1 and R2 must be the same as the potential between R3 and R4
Thus, R1/R2 = R3/R4
Hence, R4 = R3 * R2 / R1 = 86.89 ohmsQ4
I’m not very sure what is node to datum analysis. I use my own method.
V1 = Vs = 9VBy Kirchoff’s Current Law,
(V1 – V2)/Ra = V2 / Rb + Is
(9 – V2)/10 = V2/4 + 3
V2/4 + V2/10 = 9/10 -3
V2 = -6VAlso, (V2 – V3)/Rc = Is
-6 – V3 = 30
V3 = -36V
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It's been a while since I last touched this.
Hope it's right!
Q1)
current is 1A throughout
clockwise:
voltage across resistor V=RI=14V (voltage drop)
voltage across Vs=3V (increase)
voltage across Is=11V (increase)
power given off by resistor = I2R=14W
power "absorbed" by Vs=VI=3W
power "absorbed" by Is=VI=11W
(not sure if my interpretation of absorb is right)
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Q2)
Let the 10V thingy be Vs. 10ohm resistor be r10, 9ohm resistor be r9.
According to Kirchoff's current law, iunknown =0A
First look at the loop on the right.
current through r10=1A(anticlockwise)
voltage drop across r10=Ri=10V
Next look at the loop on the left.
current through r9=1A (anticlockwise)
voltage drop across r9=Ri=9V
voltage across Is1=19V
therefore power across Is1=Vi=19W
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