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    <title>Recent Posts in 'Quantum' | sgForums.com</title>
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      <title>Quantum replied by secretliker @ Mon, 05 May 2008 16:26:24 +0800</title>
      <description>&lt;p&gt;Perfect answer. Thanks!&lt;/p&gt;</description>
      <pubDate>Mon, 05 May 2008 16:26:24 +0800</pubDate>
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      <author>secretliker</author>
      <link>http://www.sgforums.com/forums/2297/topics/316488</link>
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      <title>Quantum replied by eagle @ Mon, 05 May 2008 11:24:11 +0800</title>
      <description>&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;i) Assume UV ray is shone directly onto the film, and not at an
angle&lt;/p&gt;
&lt;p&gt;Energy of photon = h*c/wavelength = 5.525e-19 J&lt;br /&gt;
Intensity is 20Wm-2, so for the exposed area, power is 3e-8 W&lt;/p&gt;
&lt;p&gt;Thus, number of photons incident on film in 1 second = 3e-8 /
5.525e-19 = 5.43e10 photons&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;ii) 1 photon max 1 electron emission&lt;/p&gt;
&lt;p&gt;so 1% means 5.43e8 electrons&lt;br /&gt;
electron charge = 1.6e-19 C&lt;/p&gt;
&lt;p&gt;So total charge in 20 mins = 5.43e8 * 1.6e-19 * (20 *60 s) =
1.043e-7 C&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;The photon must have the exact energy/frequency (E=hf) to be
able to cause the photoemission of exactly one electron. This means
that only UV photons in this case has the right amount of energy to
cause photoemission.&lt;/p&gt;
&lt;p&gt;Since sunlight consist of various wavelengths of light, UV rays
are only a fraction of sunlight (and thus fraction of the
intensity). Hence, the amount of power from UV rays from sunlight
will be lower than the original intensity of the UV ray in the
first part of this question. This results in a slower erasure rate
since less photoemission will result.&lt;/p&gt;</description>
      <pubDate>Mon, 05 May 2008 11:24:11 +0800</pubDate>
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      <author>eagle</author>
      <link>http://www.sgforums.com/forums/2297/topics/316488</link>
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      <title>Quantum replied by secretliker @ Sun, 04 May 2008 22:07:42 +0800</title>
      <description>&lt;p&gt;The memory of a computer element can be erased by exposing it to
ultra-violet radiation of wavelength 360nm for 20 minutes. The
memory is contained in an insulated silicon film of exposed area
1.5 X 10^-9 m-2, and the intensity of the UV light of 20Wm-2.&lt;/p&gt;
&lt;p&gt;&lt;strong&gt;Calculate&lt;/strong&gt;&lt;/p&gt;
&lt;p&gt;(i) The number of photons incident on the film in 1 second&lt;/p&gt;
&lt;p&gt;(ii) The charge acquired by the film in 20 minutes of exposure,
if 1% of the incident photons cause photoemission of electrons.&lt;/p&gt;
&lt;p&gt;Explain why erasure would be slower if the memory were exposed
to sunlight of the same total intensity.&lt;/p&gt;</description>
      <pubDate>Sun, 04 May 2008 22:07:42 +0800</pubDate>
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      <author>secretliker</author>
      <link>http://www.sgforums.com/forums/2297/topics/316488</link>
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