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Hey guys, i need help with this question:
BLock of ice ( 0 degC ) has a hollow in its top surface.
160g of water ( 100degC ) is poured into the hollow. Heat capacity of water is 4.20kJ/kg/K
Some ices melts and the mass of water in the hollow is now 365g.
Assuming no atmosphere-related heat gain, find specific latent heat of fusion of Ice.
Here I did it this way:
Q( Heat lost by 160g water) = Q( Heat gained by (365-160= 205g) of Ice)
hence:
ml(f) = ml(f)
(0.205)( l(f) ) = (0.160)(4200)
l(f) = 3.28kJ/kg/K
Correct?
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Your answer should be 3.28 * 10^2 kJ/kg/K
Heat lost by 160g water = Heat gained by 205g ice
m*c*(change in Temp) = m*(latent heat of fusion)
0.160 * 4200 * (100-0) (you left this out) = 0.205 * (latent heat of fusion)
latent heat of fusion = 327804 = 3.28 * 10^2 kJ/kg/K
Edited by secretliker 05 May `08, 2:22AM
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