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    <title>Recent Posts in 'f(x) to f'(x) graphs help.' | sgForums.com</title>
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      <title>f(x) to f'(x) graphs help. replied by limywv @ Sat, 14 Jun 2008 01:12:14 +0800</title>
      <description>&lt;p&gt;thanks&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;</description>
      <pubDate>Sat, 14 Jun 2008 01:12:14 +0800</pubDate>
      <guid isPermaLink="false">sgforums.com:2297:320896:8164900</guid>
      <author>limywv</author>
      <link>http://sgforums.com/forums/2297/topics/320896</link>
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      <title>f(x) to f'(x) graphs help. replied by eagle @ Sat, 14 Jun 2008 00:53:05 +0800</title>
      <description>&lt;blockquote&gt;
&lt;div class="quote_from"&gt;Originally posted by limywv:&lt;/div&gt;
&lt;div class="quote_body"&gt;
&lt;p&gt;thanks for the reply, but am I right by spltting the f graph
into 4 parts, the most-left portion i see it as having a decreasing
Positive&amp;nbsp;gradient, so the f' graph for that part&amp;nbsp;should
be on the positive y&amp;nbsp;plane&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;Ok so how about the next qn, i seriously not sure of it..&lt;/p&gt;
&lt;/div&gt;
&lt;/blockquote&gt;
&lt;p&gt;the left-most part is actually increasing positive gradient. Do
look again. Decreasing means you should see it tending to a turning
point again.&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;the next question, do it the same way as you have done lor....
when x is -ve infinity or infinity, f'(x) = 0&lt;/p&gt;
&lt;p&gt;then as x tends to zero, your f'(x) will curve up, then curve
down again to zero where f(x) is at the turning point, then curve
up again, then down back to zero again... You f'(x) graph will look
something like a camel double hump&lt;/p&gt;</description>
      <pubDate>Sat, 14 Jun 2008 00:53:05 +0800</pubDate>
      <guid isPermaLink="false">sgforums.com:2297:320896:8164863</guid>
      <author>eagle</author>
      <link>http://sgforums.com/forums/2297/topics/320896</link>
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    <item>
      <title>f(x) to f'(x) graphs help. replied by limywv @ Sat, 14 Jun 2008 00:50:10 +0800</title>
      <description>&lt;p&gt;thanks for the reply, but am I right by spltting the f graph
into 4 parts, the most-left portion i see it as having a decreasing
Positive&amp;nbsp;gradient, so the f' graph for that part&amp;nbsp;should
be on the positive y&amp;nbsp;plane&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;Ok so how about the next qn, i seriously not sure of it..&lt;/p&gt;</description>
      <pubDate>Sat, 14 Jun 2008 00:50:10 +0800</pubDate>
      <guid isPermaLink="false">sgforums.com:2297:320896:8164851</guid>
      <author>limywv</author>
      <link>http://sgforums.com/forums/2297/topics/320896</link>
    </item>
    <item>
      <title>f(x) to f'(x) graphs help. replied by eagle @ Sat, 14 Jun 2008 00:44:45 +0800</title>
      <description>&lt;p&gt;looks almost correct&lt;/p&gt;
&lt;p&gt;but as x tends to infinity or - infinity, i seems that the
gradient increases faster and faster... So your red curve shouldn't
really be concave downwards at both ends I think...&lt;/p&gt;</description>
      <pubDate>Sat, 14 Jun 2008 00:44:45 +0800</pubDate>
      <guid isPermaLink="false">sgforums.com:2297:320896:8164843</guid>
      <author>eagle</author>
      <link>http://sgforums.com/forums/2297/topics/320896</link>
    </item>
    <item>
      <title>f(x) to f'(x) graphs help. replied by limywv @ Sat, 14 Jun 2008 00:35:58 +0800</title>
      <description>&lt;p&gt;hey guys, got a question to ask...it's H2 maths, regarding f(x)
to f'(x) graphs..I've included a scan so pls correct me if i'm
wrong.&lt;/p&gt;
&lt;p&gt;&amp;nbsp;thanks.&lt;/p&gt;
&lt;p&gt;&lt;img src="http://img81.imageshack.us/img81/4536/picturepk8.jpg"
height="636" alt="sd" width="640" /&gt;&lt;/p&gt;</description>
      <pubDate>Sat, 14 Jun 2008 00:35:58 +0800</pubDate>
      <guid isPermaLink="false">sgforums.com:2297:320896:8164814</guid>
      <author>limywv</author>
      <link>http://sgforums.com/forums/2297/topics/320896</link>
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