<?xml version="1.0" encoding="UTF-8"?>
<rss xmlns:atom="http://www.w3.org/2005/Atom" xmlns:opensearch="http://a9.com/-/spec/opensearch/1.1/" version="2.0">
  <channel>
    <title>Recent Posts in 'Need workings for this sec 3NA maths question' | sgForums.com</title>
    <link>http://sgforums.com/forums/2297/topics/324456</link>
    <language>en-US</language>
    <ttl>60</ttl>
    <atom:link rel="search" type="application/opensearchdescription+xml" href="http://sgforums.com/open_search.xml"/>
    <description></description>
    <item>
      <title>Need workings for this sec 3NA maths question replied by weewee @ Thu, 17 Jul 2008 22:45:33 +0800</title>
      <description>&lt;p&gt;Oops correct&lt;/p&gt;</description>
      <pubDate>Thu, 17 Jul 2008 22:45:33 +0800</pubDate>
      <guid isPermaLink="false">sgforums.com:2297:324456:8249606</guid>
      <author>weewee</author>
      <link>http://sgforums.com/forums/2297/topics/324456</link>
    </item>
    <item>
      <title>Need workings for this sec 3NA maths question replied by wishboy @ Thu, 17 Jul 2008 22:31:41 +0800</title>
      <description>&lt;p&gt;b)&lt;/p&gt;
&lt;p&gt;Gradient of QR = -1/3&lt;/p&gt;
&lt;p&gt;Using coords of Q, eqn of QR is&lt;br /&gt;
y - 4 = -1/3 (x - 3)&lt;br /&gt;
y = (-1/3)x + 5&lt;/p&gt;
&lt;p&gt;a)&lt;/p&gt;
&lt;p&gt;since the lines&lt;/p&gt;
&lt;p&gt;y = 3x + 7 and y = (-1/3)x + 5&lt;/p&gt;
&lt;p&gt;intersect at R, use simultaneous eqn to get the coords of R&lt;/p&gt;
&lt;p&gt;3x + 7 = (-1/3)x + 5&lt;br /&gt;
(10/3)x = -2&lt;br /&gt;
x = -3/5&lt;/p&gt;
&lt;p&gt;Sub x = -3/5 into any of the 2 eqn&lt;/p&gt;
&lt;p&gt;y = 3(-3/5) + 7&lt;br /&gt;
y = 26/5&lt;/p&gt;
&lt;p&gt;so R = ( -3/5 , 26/5 )&lt;/p&gt;</description>
      <pubDate>Thu, 17 Jul 2008 22:31:41 +0800</pubDate>
      <guid isPermaLink="false">sgforums.com:2297:324456:8249573</guid>
      <author>wishboy</author>
      <link>http://sgforums.com/forums/2297/topics/324456</link>
    </item>
    <item>
      <title>Need workings for this sec 3NA maths question replied by 77th Cloud @ Thu, 17 Jul 2008 14:45:54 +0800</title>
      <description>&lt;p&gt;Let R = (a,b)&lt;br /&gt;
&lt;br /&gt;
4 - b / 3 - a = -1/3&lt;br /&gt;
&lt;br /&gt;
sub a, b into y = 3x+ 7&lt;br /&gt;
&lt;br /&gt;
(b&amp;nbsp; - 7 )/3 = a&lt;br /&gt;
&lt;br /&gt;
simul.&lt;br /&gt;
&amp;nbsp;&lt;br /&gt;
12 - 3b = (a - 3)&lt;br /&gt;
15 - 3b = (b-7/3)&lt;br /&gt;
45 - 9b = b - 7&lt;br /&gt;
10b = 52&lt;br /&gt;
b = 5.2 = 5/1/5&lt;br /&gt;
&lt;br /&gt;
a = (5/1/5 - 7) / 3&lt;br /&gt;
&amp;nbsp;&amp;nbsp; =&amp;nbsp; -3/5&lt;br /&gt;
&lt;br /&gt;
R = (-3/5 ; 5/1/5)&lt;/p&gt;
&lt;p&gt;Gradient QR: (4- 5/1/5) / 3- (-3/5) =&lt;br /&gt;
equation = y = (gradient)x + c&lt;br /&gt;
then just sub 3/4 into it.&lt;br /&gt;
&lt;br /&gt;
.should know if ur a teacher&lt;br /&gt;
maybe theres a shorter method, havent touched maths for one year,
but this is what i would do&lt;/p&gt;</description>
      <pubDate>Thu, 17 Jul 2008 14:45:54 +0800</pubDate>
      <guid isPermaLink="false">sgforums.com:2297:324456:8248441</guid>
      <author>77th Cloud</author>
      <link>http://sgforums.com/forums/2297/topics/324456</link>
    </item>
    <item>
      <title>Need workings for this sec 3NA maths question replied by syncopation_music @ Thu, 17 Jul 2008 12:09:04 +0800</title>
      <description>&lt;p&gt;Hi all, currently teaching a sec 3 NA student ,but really dun
quite understand how to derive the answer .I need help to get the
detailed workings .Thanks&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;There are 2 points P(-2,1) and Q(3,4) in the coordinate plane .A
line with equation y=3x+7 passes through P . R is a point on the
line such that gradient of RQ = [-1/3]&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;
&lt;p&gt;Find&lt;/p&gt;
&lt;p&gt;(a) the coordinates of
R&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;
answer :&amp;nbsp;&amp;nbsp;([-3/5],[5/1/5])&lt;/p&gt;
&lt;p&gt;(b)the equation of
QR&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;answer
:&amp;nbsp; (y=(-1/3)x+5)&amp;nbsp;&lt;/p&gt;
&lt;p&gt;&amp;nbsp;&lt;/p&gt;</description>
      <pubDate>Thu, 17 Jul 2008 12:09:04 +0800</pubDate>
      <guid isPermaLink="false">sgforums.com:2297:324456:8248022</guid>
      <author>syncopation_music</author>
      <link>http://sgforums.com/forums/2297/topics/324456</link>
    </item>
  </channel>
</rss>
