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A maths - linear law

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  • bonkysleuth's Avatar
    314 posts since Mar '07
    • the table shows experimental values of variables x and y.

       

      x - 0.25 | 0.5 | 1.0 | 1.5 | 2.5 | 6.0 | 9.0

       

      y - 1.29 | 2.24 | 3.61 | 4.50 | 5.63 | 7.20 | 7.70 | 

       

      it is known that x and y are related by an equation of the form xy + ay = bx/ using the vertical axis for y and horizontal axis for y / x, draw a straight line graph of y against y/x for given data. use graph to estimate

      (a) value of a and b

      (b) value of x for which y = 4x

       

      please help with the second part of the question. thanks. anyway, a = 1.5 and b = 9, for your reference purposes.

  • LatecomerX's Avatar
    2,331 posts since May '07
    • My maths is a little rusty, but anyway, here it goes:

      xy + ay = bx, so

      y(x + a) = bx, and

      y = bx / (x + a), and if you substitute the values,

      y = 9x / x + 1.5

      y = [9 / (x + 1.5)]x (bring the x out so that it is similar to the y = 4x equation)

      9 / (x + 1.5) = 4

      x = 9/4 - 1.5

      x = 0.75

       

  • Moderator
    eagle's Avatar
    17,967 posts since Aug '01
    • The question asks you to find using the graph.

      xy + ay = bx
      y= -a (y/x) + b, in which you have found a and b

      so for part b
      when y=4x, y/x = 4

      Since y/x is the X-axis, you draw a vertical line upwards at y/x = 4 (similar to drawing the graph x=4 in a graph with x-axis).

      You should be able to estimate the value of y at the intersection point. Divide the estimate by 4 and you get the value of x.

       

      To check if you are correct:

      xy + ay = bx
      Sub y=4x, a=1.5, b=9
      4x^2 + 6x = 9x
      4x^2 - 3x = 0
      x(4x-3) = 0
      Solving, x=0 or x=0.75

       

      Eagle
      Owner of Strategic Tuition

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