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Originally posted by jiaxing2:
skythewood's solution is correct...its probably a typo (should be ln instead of log)
stop dismissing ppl's solution like ur a big f+++
part 2 is nt tough at all...tan x / ( 1 + tanx ) = sinx / (sinx +cos x)
consider intergral of (cosx-sinx)/(sinx + cos x) = ln (sinx + cosx ) ...then Let Y =
(cosx-sinx)/(sinx + cos x) , Z = sinx / (sinx +cos x)
1-2Z = Y
Z = (1-Y)/2
thus its intergral = 0.5 (x- ln (sinx + cosx ))
and hence subbing in the values answer is pi/4...
i decline to comment on part (i)...serves no mathematical meaning...if u want challenge go solve this :
find the number of digits in n! .....
Your part 2 is right.
Instead of In, skythewood type log .. it is still wrong. So i ask him for the answer which he happily reply sub in yourself. Not bad huh! damn proud. Even got the gut to say my FM teacher is bo liao. No bad.
Your n!, I will get back to it.
U say part 1 has not mathematical meaning, well tell me why does principal argument in complex number exists?
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Originally posted by skythewood:
thread starter big fuck?
anyone who dare say e ^ (-x) = 1..... not very smart. use a calculator and calculate that.
than you will tell me have to include this part "When there is no restriction to the argument," hey, suddenly, new rules.
you can make your assumptions, i can make mine. get lost.
Every statement u make, makes u look more like a fool. Continue this shit ya.And don't bother insult my FM teacher as bo liao because idiots like you are borned to fail in life.
Edited by Uncertain 05 Oct `08, 2:24PM
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Originally posted by skythewood:
zzzzz.....
get lost lah....
Use your pig brain and think. This is my thread, u should be the one getting lost.
Ans to part 1:
By Euler's rule: re^(ix) = rcos x + i rsin x
1 = 1 e^(i 2nx) where x = pie.
When there is no restriction to the argument,
1 = 1e^0 = 1 e^-x = 1 e^x = .....
Therefore, 1 + 1 = 1e^x + 1e^-x which is not equal to 2. In general, 1 + 1 is not equal to 2.
For 1 +1 = 2, the argument of the complex number 1 has to be restricted to the principal argument -pie < x <= pie. In this case, 1e^0 is the actual value we have being using in real life.
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Originally posted by secretliker:
When 0.99999... is taken as a number that is equal to 1.
http://en.wikipedia.org/wiki/0.999...
Thus 1 + 1 = 0.99999... + 0.99999... = 1.99999...8
The sum of these 2 recurring decimals will eventually end at an imaginary 8.
haha no la. More difficult and logical than this ;)I will post the solution for part 1 tmr. Part 2 is really tough, i am not kidding.
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skythewood,
don't know how to do then shut up. Don't try to act smart here.
your first assumption about 3 s.f. is utter bullshit to begin with and u are setting your own rule (complex number is a hint to the answer). Second part only got to show ur integration skill is like shit.
Edited by Uncertain 04 Oct `08, 2:04PM
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Originally posted by skythewood:
just assume 3 sig fig
1 is understood to be 1.00 and has a range of 0.995 to 1.0049999....
hence, it is not taken for granted that 1 + 1 is equal to 2.00 in general
it will be equal to 2.00 if the result of the addition is from 1.995 to 2.004999999.....
your FM teacher is just being bo liao
-.- think along complex number.
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Originally posted by Mikethm:
Yes Yes I know you are talking about H2 maths.The point is that THEY CHANGED the O level A Maths to fit in with the progression to H2 Maths. They are linked.
Saying that the O and A are general certification does NOT mean you are learning for the paper chase. It simply mean the focus of the syllabus is to equip the student with the foundation in whatever subject examined. As to the attitude of the student, it depend on the individual. Eg. A student learning complicated sketching techniques so that he can sketch for the exams if the GC break down... is learning for the sake of examinations. A student satisfied with concepts of graphs and more than happy to let the GC/Computer do the actual mechnical aspects is learning for the sake of knowledge. Why? Because it is a fact that in real life, one can rely on computer to sketch BUT need the concept base knowledge to understand the output.
And if we disagree on the importance of the need for manual complicated graph sketching, just let it lie. Opinions are opinions. And the only one that matters is your own. Because in your mind, you are always right. Thus no point arguing about this.
If u think ur GC can draw graph, i challenge u to use your GC to draw the graph (ax+b) / (cx +d) where a, b,c, d are constants . Tell me all the asymptotes from your GC.
If not fair, use ur GC again draw the graph 4(x+4)^2 - (y-2)^2 = 1. Tell me the asymptotes.
I want to see how ur mighty GC gives me all these answers.
Edited by eagle 02 Oct `08, 2:38PM
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Originally posted by Mikethm:
Ah ha I was waiting for someone to say... "if ur GC break down in the exams...". The point is... are you learning for the sake of knowledge or for the sake of examinations? :)
And let's say it really break down... do you think you have time to find turning points, asymptotes roots etc etc manually in an exam which timing allocations is geared toward use of electronic aids even if you are reasonably proficient at it?
2nd question is invalid as the concepts are still properly taught in A Maths beforehand except that you do not go in depth. They still test asymptotes plus behaviour as curve approach asymoptotes and infinity, turning points, roots and etc in GCE O level A Maths. Just that they are used in basic scenarios and not explored at large. Please do not forget that the O and A are GENERAL certifications of education... not specialised certifications. They should only need to provide a foundation which will equip a student to have a broad superfical understanding of the subject matter. Should a student choose to go further in specialisations... what do you think degree courses are for? Of course we expect maths degree holders to program, not A level students. In society, the majority only need a broad understanding of subjects while a small minority specialises. Your friendly housewife need only to know how to cook a variety of homecook dishes... and when you want to eat Man Han full banquet... you go to the chefs.
Ok cool... so it is no good to rely on the chefs to dish up Man Han full banquet and every housewives should know how to prepare these eh?
Well Mikethm, I cannot change your thinking. But if u ever want to pursue study in university especially in the finance sector or mathematices field, then good luck to u.
As what purpledragon had said, it is possible to do all math questions with scientific calculator. The only time i use my GC is for my matrix reduced-row echleon form and my Further Mathematics teacher taught us this topic by first telling us to do it the brute force way. I admit it is tough but is enriching which make some of my courses a brisk.
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(1) use your data booklet, look at E potential of H, Cu, Ag, Li. Last one is confirmed out cos only K+ ion present.
Li, as compared to H, is negative E potential that means it is more preferred to exist as Li+. So H2 is liberated.
Cu and Ag, as compared to H, are positive E potential that means that are more preferred to be reduced. So Cu and Ag metal are deposited.
(2) Ideal gas assumptions are negligible intermolecular forces and negligible volume. Nothing to do with different speed.
(3) Ar = 108 can only means silver which can only have a charge of +1.
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